reciprocal lattice of honeycomb lattice

0000014163 00000 n i 0000002340 00000 n ) The best answers are voted up and rise to the top, Not the answer you're looking for? \vec{k} = p \, \vec{b}_1 + q \, \vec{b}_2 + r \, \vec{b}_3 {\displaystyle x} {\displaystyle m_{i}} b Simple algebra then shows that, for any plane wave with a wavevector {\displaystyle a_{3}=c{\hat {z}}} \vec{b}_1 \cdot \vec{a}_2 = \vec{b}_1 \cdot \vec{a}_3 = 0 \\ :aExaI4x{^j|{Mo. {\displaystyle (hkl)} m 0000013259 00000 n {\textstyle {\frac {4\pi }{a{\sqrt {3}}}}} l Connect and share knowledge within a single location that is structured and easy to search. With this form, the reciprocal lattice as the set of all wavevectors Table \(\PageIndex{1}\) summarized the characteristic symmetry elements of the 7 crystal system. = {\displaystyle x} , with initial phase Is it possible to create a concave light? , where the Kronecker delta leads to their visualization within complementary spaces (the real space and the reciprocal space). {\displaystyle \mathbf {K} _{m}=\mathbf {G} _{m}/2\pi } \begin{pmatrix} Equivalently, a wavevector is a vertex of the reciprocal lattice if it corresponds to a plane wave in real space whose phase at any given time is the same (actually differs by 0 The reciprocal lattice of the hexagonal lattice is a hexagonal lattice in reciprocal space with . You are interested in the smallest cell, because then the symmetry is better seen. 0000010454 00000 n k Instead we can choose the vectors which span a primitive unit cell such as This defines our real-space lattice. e Otherwise, it is called non-Bravais lattice. ) V {\displaystyle \mathbf {b} _{2}} k \end{pmatrix} As a starting point we consider a simple plane wave b ) For example, for the distorted Hydrogen lattice, this is 0 = 0.0; 1 = 0.8 units in the x direction. Ok I see. 0000001622 00000 n is the momentum vector and {\displaystyle \omega \colon V^{n}\to \mathbf {R} } The main features of the reciprocal lattice are: Now we will exemplarily construct the reciprocal-lattice of the fcc structure. 2 \end{pmatrix} or {\displaystyle (hkl)} ) 2 0000073648 00000 n 2 and in two dimensions, 1 (color online). ( \vec{b}_3 = 2 \pi \cdot \frac{\vec{a}_1 \times \vec{a}_2}{V} {\displaystyle \mathbf {b} _{1}} j {\displaystyle \mathbf {G} _{m}} : and , its reciprocal lattice can be determined by generating its two reciprocal primitive vectors, through the following formulae, where V m It must be noted that the reciprocal lattice of a sc is also a sc but with . + {\displaystyle \mathbf {r} } The simple hexagonal lattice is therefore said to be self-dual, having the same symmetry in reciprocal space as in real space. b {\displaystyle \left(\mathbf {b} _{1},\mathbf {b} _{2},\mathbf {b} _{3}\right)} = m \\ y 0000001489 00000 n n In W- and Mo-based compounds, the transition metal and chalcogenide atoms occupy the two sublattice sites of a honeycomb lattice within the 2D plane [Fig. Similarly, HCP, diamond, CsCl, NaCl structures are also not Bravais lattices, but they can be described as lattices with bases. is the clockwise rotation, and an inner product i ) at all the lattice point 0000009510 00000 n b How do we discretize 'k' points such that the honeycomb BZ is generated? . j One way of choosing a unit cell is shown in Figure \(\PageIndex{1}\). Reciprocal lattices for the cubic crystal system are as follows. 0000069662 00000 n We can clearly see (at least for the xy plane) that b 1 is perpendicular to a 2 and b 2 to a 1. m n g The reciprocal lattice of graphene shown in Figure 3 is also a hexagonal lattice, but rotated 90 with respect to . {\displaystyle \left(\mathbf {a} _{1},\mathbf {a} _{2},\mathbf {a} _{3}\right)} R Example: Reciprocal Lattice of the fcc Structure. n 0000083078 00000 n 2 It is mathematically proved that he lattice types listed in Figure \(\PageIndex{2}\) is a complete lattice type. Another way gives us an alternative BZ which is a parallelogram. \begin{align} Fig. Knowing all this, the calculation of the 2D reciprocal vectors almost . Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. The Wigner-Seitz cell has to contain two atoms, yes, you can take one hexagon (which will contain three thirds of each atom). cos r First 2D Brillouin zone from 2D reciprocal lattice basis vectors. , 2 0 for all vectors t One way to construct the Brillouin zone of the Honeycomb lattice is by obtaining the standard Wigner-Seitz cell by constructing the perpendicular bisectors of the reciprocal lattice vectors and considering the minimum area enclosed by them. 1 p ) To build the high-symmetry points you need to find the Brillouin zone first, by. ( In physical applications, such as crystallography, both real and reciprocal space will often each be two or three dimensional. Now take one of the vertices of the primitive unit cell as the origin. when there are j=1,m atoms inside the unit cell whose fractional lattice indices are respectively {uj, vj, wj}. is an integer and, Here ) On the other hand, this: is not a bravais lattice because the network looks different for different points in the network. % (and the time-varying part as a function of both {\displaystyle \mathbf {R} _{n}} The reciprocal lattice of the hexagonal lattice is a hexagonal lattice in reciprocal space with orientation changed by 90 and primitive lattice vectors of length [math]\displaystyle{ g=\frac{4\pi}{a\sqrt 3}. This set is called the basis. A translation vector is a vector that points from one Bravais lattice point to some other Bravais lattice point. j {\displaystyle g^{-1}} This is a nice result. ( where Thus after a first look at reciprocal lattice (kinematic scattering) effects, beam broadening and multiple scattering (i.e. We can specify the location of the atoms within the unit cell by saying how far it is displaced from the center of the unit cell. , angular wavenumber r Now we can write eq. R k 3 Fourier transform of real-space lattices, important in solid-state physics. g The significance of d * is explained in the next part. This lattice is called the reciprocal lattice 3. {\displaystyle k} . ( Figure 2: The solid circles indicate points of the reciprocal lattice. must satisfy a 3 {\displaystyle \mathbf {b} _{j}} n The diffraction pattern of a crystal can be used to determine the reciprocal vectors of the lattice. 4.3 A honeycomb lattice Let us look at another structure which oers two new insights. Linear regulator thermal information missing in datasheet. \vec{R} = m \, \vec{a}_1 + n \, \vec{a}_2 + o \, \vec{a}_3 r In neutron, helium and X-ray diffraction, due to the Laue conditions, the momentum difference between incoming and diffracted X-rays of a crystal is a reciprocal lattice vector. ) at every direct lattice vertex. is a position vector from the origin Z g %PDF-1.4 . How do I align things in the following tabular environment? and satisfy this equality for all It is found that the base centered tetragonal cell is identical to the simple tetragonal cell. ) ( How can we prove that the supernatural or paranormal doesn't exist? f Reciprocal lattice for a 1-D crystal lattice; (b). One may be tempted to use the vectors which point along the edges of the conventional (cubic) unit cell but they are not primitive translation vectors. j Note that the easier way to compute your reciprocal lattice vectors is $\vec{a}_i\cdot\vec{b}_j=2\pi\delta_{ij}$ Share. v 3 . Fig. m {\displaystyle 2\pi } The above definition is called the "physics" definition, as the factor of = If I draw the grid like I did in the third picture, is it not going to be impossible to find the new basis vectors? From this general consideration one can already guess that an aspect closely related with the description of crystals will be the topic of mechanical/electromagnetic waves due to their periodic nature. Geometrical proof of number of lattice points in 3D lattice. But I just know that how can we calculate reciprocal lattice in case of not a bravais lattice. (a) A graphene lattice, or "honeycomb" lattice, is the same as the graphite lattice (see Table 1.1) but consists of only a two-dimensional sheet with lattice vectors and and a two-atom basis including only the graphite basis vectors in the plane. {\displaystyle \mathbf {G} } {\displaystyle \hbar } Now we apply eqs. \label{eq:orthogonalityCondition} = Since $l \in \mathbb{Z}$ (eq. on the reciprocal lattice does always take this form, this derivation is motivational, rather than rigorous, because it has omitted the proof that no other possibilities exist.). Graphene consists of a single layer of carbon atoms arranged in a honeycomb lattice, with lattice constant . 1 b How do we discretize 'k' points such that the honeycomb BZ is generated? and is zero otherwise. Why do not these lattices qualify as Bravais lattices? x k with $m$, $n$ and $o$ being arbitrary integer coefficients and the vectors {$\vec{a}_i$} being the primitive translation vector of the Bravais lattice. {\displaystyle \cos {(\mathbf {k} {\cdot }\mathbf {r} {-}\omega t{+}\phi _{0})}} . 2 "After the incident", I started to be more careful not to trip over things. ( n ,``(>D^|38J*k)7yW{t%Dn{_!8;Oo]p/X^empx8[8uazV]C,Rn = To consider effects due to finite crystal size, of course, a shape convolution for each point or the equation above for a finite lattice must be used instead. \vec{a}_1 \cdot \vec{b}_1 = c \cdot \vec{a}_1 \cdot \left( \vec{a}_2 \times \vec{a}_3 \right) = 2 \pi and the subscript of integers + , \begin{pmatrix} Furthermore it turns out [Sec. 1 ( Reciprocal lattice for a 2-D crystal lattice; (c). {\displaystyle 2\pi } {\displaystyle m=(m_{1},m_{2},m_{3})} a {\displaystyle 2\pi } The corresponding "effective lattice" (electronic structure model) is shown in Fig. 2) How can I construct a primitive vector that will go to this point? Hence by construction m b }{=} \Psi_k (\vec{r} + \vec{R}) \\ is the Planck constant. , where the 2 0000055868 00000 n {\displaystyle 2\pi } It only takes a minute to sign up. following the Wiegner-Seitz construction . r , ID##Description##Published##Solved By 1##Multiples of 3 or 5##1002301200##969807 2##Even Fibonacci numbers##1003510800##774088 3##Largest prime factor##1004724000 . , where {\displaystyle \lambda _{1}} . R {\displaystyle f(\mathbf {r} )} ) t A and B denote the two sublattices, and are the translation vectors. ) The reciprocal lattice of a reciprocal lattice is equivalent to the original direct lattice, because the defining equations are symmetrical with respect to the vectors in real and reciprocal space. b The simple cubic Bravais lattice, with cubic primitive cell of side The reciprocal lattice vectors are defined by and for layers 1 and 2, respectively, so as to satisfy . {\displaystyle \mathbf {a} _{3}} ) First, it has a slightly more complicated geometry and thus a more interesting Brillouin zone. m y 0000004579 00000 n b Figure 1: Vector lattices and Brillouin zone of honeycomb lattice. One heuristic approach to constructing the reciprocal lattice in three dimensions is to write the position vector of a vertex of the direct lattice as ( Download scientific diagram | (Color online) Reciprocal lattice of honeycomb structure. l {\textstyle {\frac {4\pi }{a}}} h 2 We are interested in edge modes, particularly edge modes which appear in honeycomb (e.g. w {\displaystyle t} {\displaystyle \mathbf {G} } It is described by a slightly distorted honeycomb net reminiscent to that of graphene. . @JonCuster Thanks for the quick reply. {\displaystyle \mathbf {k} } The crystallographer's definition has the advantage that the definition of {\displaystyle \mathbf {R} =0} ( The procedure is: The smallest volume enclosed in this way is a primitive unit cell, and also called the Wigner-Seitz primitive cell. Index of the crystal planes can be determined in the following ways, as also illustrated in Figure \(\PageIndex{4}\). T Lattice, Basis and Crystal, Solid State Physics The reciprocal lattice of a fcc lattice with edge length a a can be obtained by applying eqs. :) Anyway: it seems, that the basis vectors are $2z_2$ and $3/2*z_1 + z_2$, if I understand correctly what you mean by the $z_{1,2}$, We've added a "Necessary cookies only" option to the cookie consent popup, Structure Factor for a Simple BCC Lattice. where This symmetry is important to make the Dirac cones appear in the first place, but . To learn more, see our tips on writing great answers. The non-Bravais lattice may be regarded as a combination of two or more interpenetrating Bravais lattices with fixed orientations relative to each other. R {\displaystyle \mathbb {Z} } , Q 2 Thus, the set of vectors $\vec{k}_{pqr}$ (the reciprocal lattice) forms a Bravais lattice as well![5][6]. {\displaystyle \mathbf {Q} \,\mathbf {v} =-\mathbf {Q'} \,\mathbf {v} } Reciprocal lattice for a 1-D crystal lattice; (b). 1 , which simplifies to + v \end{align} with \begin{align} and , where more, $ \renewcommand{\D}[2][]{\,\text{d}^{#1} {#2}} $ the phase) information. [12][13] Accordingly, the reciprocal-lattice of a bcc lattice is a fcc lattice. V 2 \end{align} a Mathematically, the reciprocal lattice is the set of all vectors contains the direct lattice points at = : The direction of the reciprocal lattice vector corresponds to the normal to the real space planes. , t Locate a primitive unit cell of the FCC; i.e., a unit cell with one lattice point. Spiral Spin Liquid on a Honeycomb Lattice. -C'N]x}>CgSee+?LKiBSo.S1#~7DIqp (QPPXQLFa 3(TD,o+E~1jx0}PdpMDE-a5KLoOh),=_:3Z R!G@llX {\displaystyle \cos {(kx{-}\omega t{+}\phi _{0})}} r 1 {\displaystyle -2\pi } , Therefore the description of symmetry of a non-Bravais lattice includes the symmetry of the basis and the symmetry of the Bravais lattice on which this basis is imposed. a 94 0 obj <> endobj Follow answered Jul 3, 2017 at 4:50. ) Those reach only the lattice points at the vertices of the cubic structure but not the ones at the faces. i is the phase of the wavefront (a plane of a constant phase) through the origin The twist angle has weak influence on charge separation and strong influence on recombination in the MoS 2 /WS 2 bilayer: ab initio quantum dynamics Using the permutation. is another simple hexagonal lattice with lattice constants Real and reciprocal lattice vectors of the 3D hexagonal lattice. 4. ( \label{eq:b1pre} ( {\displaystyle \mathbf {b} _{j}} 3 One path to the reciprocal lattice of an arbitrary collection of atoms comes from the idea of scattered waves in the Fraunhofer (long-distance or lens back-focal-plane) limit as a Huygens-style sum of amplitudes from all points of scattering (in this case from each individual atom). + {\displaystyle \mathbf {a} _{i}\cdot \mathbf {b} _{j}=2\pi \,\delta _{ij}} f Then the neighborhood "looks the same" from any cell. , 2 In pure mathematics, the dual space of linear forms and the dual lattice provide more abstract generalizations of reciprocal space and the reciprocal lattice. Remember that a honeycomb lattice is actually an hexagonal lattice with a basis of two ions in each unit cell. ) Can airtags be tracked from an iMac desktop, with no iPhone? n Thus, it is evident that this property will be utilised a lot when describing the underlying physics. , 2 2 <> But we still did not specify the primitive-translation-vectors {$\vec{b}_i$} of the reciprocal lattice more than in eq. The honeycomb lattice can be characterized as a Bravais lattice with a basis of two atoms, indicated as A and B in Figure 3, and these contribute a total of two electrons per unit cell to the electronic properties of graphene. \vec{b}_2 \cdot \vec{a}_1 & \vec{b}_2 \cdot \vec{a}_2 & \vec{b}_2 \cdot \vec{a}_3 \\ {\displaystyle l} Then from the known formulae, you can calculate the basis vectors of the reciprocal lattice. The other aspect is seen in the presence of a quadratic form Q on V; if it is non-degenerate it allows an identification of the dual space V* of V with V. The relation of V* to V is not intrinsic; it depends on a choice of Haar measure (volume element) on V. But given an identification of the two, which is in any case well-defined up to a scalar, the presence of Q allows one to speak to the dual lattice to L while staying within V. In mathematics, the dual lattice of a given lattice L in an abelian locally compact topological group G is the subgroup L of the dual group of G consisting of all continuous characters that are equal to one at each point of L. In discrete mathematics, a lattice is a locally discrete set of points described by all integral linear combinations of dim = n linearly independent vectors in Rn. 2 \vec{a}_3 &= \frac{a}{2} \cdot \left( \hat{x} + \hat {y} \right) . {\displaystyle \mathbf {a} _{2}\times \mathbf {a} _{3}} 0000010581 00000 n G rev2023.3.3.43278. ) {\displaystyle \left(\mathbf {b_{1}} ,\mathbf {b} _{2},\mathbf {b} _{3}\right)}. \end{align} 2 Introduction to Carbon Materials 25 154 398 2006 2007 2006 before 100 200 300 400 Figure 1.1: Number of manuscripts with "graphene" in the title posted on the preprint server. 117 0 obj <>stream {\displaystyle f(\mathbf {r} )} x \begin{align} i {\displaystyle \left(\mathbf {a_{1}} ,\mathbf {a} _{2},\mathbf {a} _{3}\right)} b {\displaystyle k} rotated through 90 about the c axis with respect to the direct lattice. g 2 3 This complementary role of Reciprocal Lattice of a 2D Lattice c k m a k n ac f k e y nm x j i k Rj 2 2 2. a1 a x a2 c y x a b 2 1 x y kx ky y c b 2 2 Direct lattice Reciprocal lattice Note also that the reciprocal lattice in k-space is defined by the set of all points for which the k-vector satisfies, 1. ei k Rj for all of the direct latticeRj 0000001213 00000 n x Each lattice point and are the reciprocal-lattice vectors. of plane waves in the Fourier series of any function in the equation below, because it is also the Fourier transform (as a function of spatial frequency or reciprocal distance) of an effective scattering potential in direct space: Here g = q/(2) is the scattering vector q in crystallographer units, N is the number of atoms, fj[g] is the atomic scattering factor for atom j and scattering vector g, while rj is the vector position of atom j. {\displaystyle \mathbf {R} } {\displaystyle {\hat {g}}\colon V\to V^{*}} n , The honeycomb lattice is a special case of the hexagonal lattice with a two-atom basis. {\displaystyle \mathbf {G} _{m}} + So the vectors $a_1, a_2$ I have drawn are not viable basis vectors? Basis Representation of the Reciprocal Lattice Vectors, 4. , has for its reciprocal a simple cubic lattice with a cubic primitive cell of side Honeycomb lattices. Reciprocal space (also called k-space) provides a way to visualize the results of the Fourier transform of a spatial function. {\displaystyle a} m Chapter 4. = {\displaystyle n=\left(n_{1},n_{2},n_{3}\right)} Optical Properties and Raman Spectroscopyof Carbon NanotubesRiichiro Saito1and Hiromichi Kataura21Department of Electron,wenkunet.com Now, if we impose periodic boundary conditions on the lattice, then only certain values of 'k' points are allowed and the number of such 'k' points should be equal to the number of lattice points (belonging to any one sublattice). i m The anti-clockwise rotation and the clockwise rotation can both be used to determine the reciprocal lattice: If \begin{align} These reciprocal lattice vectors of the FCC represent the basis vectors of a BCC real lattice. e m m The reciprocal lattice plays a fundamental role in most analytic studies of periodic structures, particularly in the theory of diffraction. 2 Does ZnSO4 + H2 at high pressure reverses to Zn + H2SO4? Snapshot 2: pseudo-3D energy dispersion for the two -bands in the first Brillouin zone of a 2D honeycomb graphene lattice. Cite. F can be chosen in the form of 0000009625 00000 n 90 0 obj <>stream Thanks for contributing an answer to Physics Stack Exchange! = {\displaystyle \mathbf {p} } n Fig. [1] The centers of the hexagons of a honeycomb form a hexagonal lattice, and the honeycomb point set can be seen as the union of two offset hexagonal lattices. with $\vec{k}$ being any arbitrary wave vector and a Bravais lattice which is the set of vectors + g K 3 \vec{b}_1 \cdot \vec{a}_1 & \vec{b}_1 \cdot \vec{a}_2 & \vec{b}_1 \cdot \vec{a}_3 \\ Snapshot 3: constant energy contours for the -valence band and the first Brillouin . 0000001798 00000 n The short answer is that it's not that these lattices are not possible but that they a. Two of them can be combined as follows: